number line begins with the number 236750 and ends with the number 300000. If the length of the increment interval is 50, and the letter y is located at A/ 236000 B 236850 C/ 236900 D/ 237000 the sixth mark from the beginning؟
إجابة الطالب المختصرة من خلال موقع بوابة الإجابات هي
D/ 237000.
Here's how to solve this:
1. **Calculate the position of the sixth mark:** Since the increment interval is 50, the sixth mark from the beginning would be 5 intervals away from the start. 5 * 50 = 250
2. **Determine the value of the sixth mark:** Add the distance calculated in step 1 to the starting number of the number line. 236750 + 250 = 237000
Therefore, the answer is D/ 237000
اذا كان لديك إجابة افضل او هناك خطأ في الإجابة علي سؤال number line begins with the number 236750 and ends with the number 300000. If the length of the increment interval is 50, and the letter y is located at A/ 236000 B 236850 C/ 236900 D/ 237000 the sixth mark from the beginning اترك تعليق فورآ.
