Two balls are each given a static electric charge q1 = q2 =10-4 C of a coulomb. 1- Calculate the force between the charges when they are separated (r = 0.1m). ke = 9 x 109 N.m2/C2 2- Compare the force with the weight of an average 70 kg person.؟
إجابة الطالب المختصرة من خلال موقع بوابة الإجابات هي
The electrostatic force between the charges is approximately 9000 N. The weight of an average 70 kg person is 686.7 N.
Okay, let's break down this problem step-by-step.
**1. Calculate the Electrostatic Force**
We'll use Coulomb's Law to calculate the force between the two charged balls:
F = k * |q1 * q2| / r^2
Where:
* F is the electrostatic force (in Newtons)
* k is Coulomb's constant (k = 9 x 10^9 N.m^2/C^2)
* q1 and q2 are the magnitudes of the charges (in Coulombs)
* r is the distance between the charges (in meters)
Plug in the given values:
F = (9 x 10^9 N.m^2/C^2) * |(10^-4 C) * (10^-4 C)| / (0.1 m)^2
F = (9 x 10^9) * (10^-8) / 0.01
F = 90 / 0.01
F = 9000 N
Therefore, the force between the two charges is 9000 Newtons.
**2. Calculate the Weight of the Person**
Weight is the force of gravity on an object, calculated as:
Weight (W) = mass (m) * acceleration due to gravity (g)
We'll use g ≈ 9.8 m/s^2 (standard acceleration due to gravity).
W = 70 kg * 9.8 m/s^2
W = 686 N
Therefore, the weight of the average person is 686 N.
**3. Compare the Force and the Weight**
To compare, we'll divide the electrostatic force by the weight of the person:
Ratio = Electrostatic Force / Weight
Ratio = 9000 N / 686 N
Ratio ≈ 13.12
**Answer:**
1. The electrostatic force between the two charges is **9000 N**.
2. The electrostatic force is approximately **13.12** times greater than the weight of an average 70 kg person. This demonstrates how strong the electrostatic force can be compared to everyday gravitational forces, even with relatively small charges.
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