Sure, I can help you with that!
In the visible spectrum of the hydrogen atom, the four colored lines are part of the Balmer series. These lines correspond to electron transitions from higher energy levels down to the n=2 energy level. The lines, from longest wavelength (lowest energy/frequency) to shortest wavelength (highest energy/frequency), are:
- Red (H$\alpha$): This line corresponds to the transition from n=3 to n=2. It has the longest wavelength and therefore the lowest frequency.
- Cyan/Aqua (H$\beta$): This line corresponds to the transition from n=4 to n=2.
- Blue (H$\gamma$): This line corresponds to the transition from n=5 to n=2.
- Violet (H$\delta$): This line corresponds to the transition from n=6 to n=2.
Therefore, the red line (H$\alpha$) has the smallest frequency among the four visible lines in the hydrogen spectrum.
اذا كان لديك إجابة افضل او هناك خطأ في الإجابة علي سؤال يتكون الطيف الخطى المرئي لذرة الهيدروجين من أربعة خطوط ملونة، أيا منها يكون تردده هو الأصغر اترك تعليق فورآ.